E^2 = (pc)^2 + (m * c^2) ^2 |
div.E = rho/Epsilon 0 curl x E = - dB/dt div.B = 0 curl x B = mu 0 (J + epsilon 0 * dE/dt) |
ih * d psi(r,t) /dt = H * psi(r,t) /dt |
F = m * a |
{H,I} = dH/dti = 0 ==> {I,H} = dI/dt = 0 |
The main problem with this law is that the law is very difficult to verify by means of an experiment because the law does not contain any direct measurable physical parameter.
delta x * delta p >= h/2 |
Delta S >=0 |
G mu v + lambda g mu v = (8 pi G / c^4) T mu v |
E^2 = (pc)^2 + (m c^2) ^2 |
F = G * m1 * m2 / r^2 |
https://insidetheperimeter.ca/wp-content/uploads/2022/03/Web_Battle-equa-slice_Equa-10.png
(da/a)^2 = (8 pi G)/3 * rho - k/a^2 + lambda/3
d2a/a = (4 pi G) /3 (rho + 3p) + lambda/3 |
F = G * m1 * m2 / r^2 |
E = hv = hc/Lambda |
https://insidetheperimeter.ca/wp-content/uploads/2022/03/Web_Battle-equa-slice_Equa-13.png
e^iPhi = cos(phi) + i sin (phi) |
https://insidetheperimeter.ca/wp-content/uploads/2022/03/Web_Battle-equa-slice_Equa-14.png
dp/dt = = -dH/dq , dq/dt = dH/dp |
https://insidetheperimeter.ca/wp-content/uploads/2022/03/Web_Battle-equa-slice_Equa-15.png
L = 4pi * R^2 * sigma * T^4 |
https://insidetheperimeter.ca/wp-content/uploads/2022/03/Web_Battle-equa-slice_Equa-16.png
Most readers will say: That is simple. The more motors you will connect the slower the other motors will rotate.
But how do they know that?
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