For the most recent modifications and additions to this page See Remarks and Objections part 2 and Literature
LS1 B LS2 FD1 <-------------------------> FD2 ---->v O O --------------------------------------------- AThe train contains at each side: a Firing Device FD and a lightsource LS (a lamp).
The paragraph "The relativity of Simultaneity" in the afore mentioned book, starts with the sentence:"Consider two events which take place at the same time, according to A, and also at two points equal but opposite distances away."
IMO two events can take place (happen) at the same time. IMO there exists a whole plane from where those two events can de observed simultaneous. You have to be at the right position and the right moment to actual observe (see) those two events simultaneous.
A establishes this by sending out one light signal, which will be reflected at the two points and which will received simultaneous by A. This is completely in agreement with the above definition of "distance of an object". However for me the big question is: did the reflection (the two events) actual happen simultaneous. I'am not sure about that.
IMO the whole idea behind the Train Thought Experiment is to start with two events which will happen simultaneous. But than the issue is: does A actual see those two events simultaneous.
You can also start from the opposite approach. A Observes something simultaneous. Issue: did what he saw actual happen simultaneous.
IMO the only way out is to actual perform this experiment. The Train Thought Experiment is not a very good yardstick to establish accurately how nature behaves i.e. to establish who sees something (that happened at the same time) simultaneous and who not.
First I would like to make three remarks:
In fact there are two issues:
In order to answer those questions you have to perform the experiment under two conditions: 1) At a speed v almost zero (This is called calibration) 2) At a speed v = large.
Length Contraction becomes an issue for any speed. That means that for any speed v (Except is v is very small) the length of the train changes and observer A does not see the two light signals simultaneous. In order to see them simultaneous you have to change the distance between the two Firing Devices.
The best way to challenge the idea that Observer A sees the two ligt signals simultaneous (During Calibration part 3) is by making a complete copy of the experiment or set up, with the only difference that you place this set up on a moving platform, which has a speed v. This copy includes the track, Firing divies and an Observer A near the track, at the centre between the two firing devices.
The question is what does Observer A on the moving platform see, when you perform the calibration step part 3. i.e. that the train has a very small speed relative to the track on the moving platform.
IMO Answer 3 is the correct answer, implying that the description of experiment 1 is wrong.
(1) There is one major difference between the two experiments: in experiment 2 length contraction is involved. This involves the whole experiment setup.
Not only the train (Such as in experiment 1) but also the distance between the 2 firing devices.
Remarks and Objections part 2
For a copy of the page in the book "Introducing Einstein's Relativity" See: Fig 2.13 Light signals emanating from the two sources
Calibration consists of three different parts:
If the length of the train is l0 than this distance is l0 - l0 * SQR(1-v^2/c^2).
This is called Experiment 2 compared with Experiment 1 previous discussed i.e. the rest frame experiment.
Three Answers are possible.
Answer 2 follows the same reasoning as what Observer B sees in experiment 1. In that case Observer A sees in Experiment 1 the two signals simultaneous and so are the events that caused those signals. In experiment 2 the events are also simultaneous and identical (1) as in experiment 1, resulting that the moving Observer A in experiment 2 can not see them simultaneous.
This is logical all correct IF Observer A in experiment sees them simultaneous. But why should there be a preference for Observer A in experiment 1 to see something simultaneous compared to Observer A in experiment 2. Both are the same experiments. Why ?
The consequences are that it is not possible to perform the two experiments in such a way that all the 2 events of each experiment (i.e. all four) are occuring simultaneous.
To bypass this offset you have to make the train on the moving platform longer. When you do that in the correct way and you perform the calibration test then from the point of view of Observer A the two tests are identical (He sees simultaneous light signals in the 2 experiments and the 4 events are all simulataneous). For Observer A in experiment 2 this modification does not make any difference: he sees the light signals not simultaneous.
Simulateity of Relativity Literature.
The following documents discuss Simultaneity of Relativity together with Length Contraction on the Internet.
This document raises four issues:
That means if you want to see two simultaneous events simultaneous, you have to change the difference between the contacts or firing devices in order to offset the length contraction.
That reasoning is completely in agreement as discussed in the above paragraph.
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Last modified: 23 Augustus 1999
Last modified: 20 March 2006
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