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c * t1 = A0B0 , A0B0 = 100: t1 = 100: B0 - B1 = 100 = A0 - A1 A0C0 = A0B0 + v * t2 = c * t2 : t2 = A0B0/(c-v) : t2 = 125 : C2 - C0 = 125 v * t3 + c* t3 = 2 * A0C0 : t3 = 2 * A0C0 / (v + c) : t3 = 208,33 D0 - D3 = 208,33 A0 - A1 = 100 , A0 - A2 = 125, A0 - A3 = 200, A0 - A4 = 250 |
Consider one sets of identical clocks, all clocks moving with the same speed, all clocks are at a fixed distance of each other, all clocks are synchronized and show the same time. This is set 1 and each clock is called clock 1.
Consider a second set of identical clocks. This is set 2 and each clock is called clock 2.
The difference beteen set 1 and set 2 that the clocks of set 2 have a speed v relative to set 1.
When you consider both sets as a total than the whole group is not synchronised implying that not all clocks can show universal time.
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Figure 1A is based on the concept that the clocks of C1 and C2 are initialized when they meet with a count of 100 and that all the clocks are synchronised with this same count using Einstein synchronisation.
In Figure 1A the difference between C1 and C2 = 0. In Figure 1B the difference between D1 and D2 = 20 and in Figure 1 C the difference is 40. That means there is a linear increase.
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This seems simple but is it correct? The problem starts when you consider clocks in a moving frame.
| | / Q | / . . / | / . x | / . . / | x . / | / . . / |/ S / -------------- |
In the picture at the left we have one source which transmits two light signals. They will both reach the point Q (Clock 2) simultaneous. When we issue a synchronisation signal of 1005, this signal will not reach the two points x simultaneous in the frame at rest. |
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Figure 3 shows the different arriving times in arbitrary direction. Clock 1 is at the origin O and clock 2 is at the position marked 2. In all the cases the signal is transmitted when T1 of clock 1 is 2000 and T2 of clock 1 is 2010. |
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Figure 4 shows the source at O and 4 four detectors marked N,E,S, and W The idea behind is to study this process from two perspectives.
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1 2 3 4 5 6 7 8 9 t0 1' 2' 3' 4' 5' 6' 7' 8' 9' --> t1 1' 2' 3' 4' 5' 6' 7' 8' 9' --> Figure 5 |
1 2 3 4 5 6 7 8 9 t1 1' 2' 3' 4' 5' 6' 7' 8' 9' --> t2 1' 2' 3' 4' 5' 6' 7' 8' 9' --> t7 1' 2' 3' 4' 5' 6' 7' 8' 9' --> t14 1' 2' 3' 4' 5' 6' 7' 8' 9' --> Figure 6 |
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